source: liacs/cvp/assignments/lecture2.txt@ 196

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[2]1# Rick van der Zwet
2# StudentID: 0433373
3# $Id: lecture2.txt 248 2007-10-04 19:37:40Z rick $
4
5All quotes are based on the 7th edition of Concepts of programming
6languages from Robert W. Sebesta, cause the 8th edition has not come in
7yet
8
9*** Chapter 3 Review Questions ***
10
112)
12Q: Who are language descriptions for?
13A: "One of the problems ... about a language" pg. 124 sect. 3.1
14
153)
16Q: Describe the operation of a general language generator
17A: "A language generator ... it is pushed" pg. 126 sect. 3.2.2
18
196)
20Q: Define a left recursive grammar rule.
21A: "In this derivation ... leftmost drivations" pg 130
22 Example: <stmt> => <stmt> , <id>
23 | <id>
24 <id> => A | B | C
25
268)
27Q: Distinguish between static and dynamic semantics.
28A: "Static semantics is .. at compile time" pg. 142 sec. 3.4.1
29
309)
31Q: What purpose do predicates service in an attribute grammer?
32A: "Predicates functions, which .. with grammar rules." pg. 142. sec. 3.4.2
33
3410)
35Q: What is the difference between a synthensized and an inherited
36 attribute?
37A: "Synthesized attributes are ... across a tree" pg. 143 sect. 3.4.3
38
3913)
40Q: What is the problem with using a software pure interpreter for
41 operation semantics?
42A: "First, the copmlexities ... configured computer." pg. 149
43
44*** Chapter 3 Problem Set ***
4519) Compute the weakest precondition for each of the following
46 assignment statements and postconditions:
47
4819a)
49Q: a = 2 * (b - 1) - 1 {a > 0}
50A: 2 * (b - 1) - 1 > 0
51A b > 1.5
52
5319b)
54Q: b = (c + 10) / 3 {b > 6}
55A: (c + 10) / 3 > 6
56 c > 8
57
5819c)
59Q: a = a + 2 * b - 1 {a > 1}
60A: a + 2 * b - 1 > 1
61 b > 0.5a + 1
62
6319d)
64Q: x = 2 * y + x - 1 {x > 11}
65A: 2 * y + x - 1 > 11
66 y > 6 - 0.5x
67
6820) Compute the weakest precondition for each of the following
69 assignment statements and postconditions:
70
7120a)
72Q: a = 2 * b + 1;
73 b = a - 3
74 {b < 0}
75A: a - 3 < 0
76 {a < 3}
77 2 * b + 1 < 3
78 {b < 1}
79
8020b)
81Q: a = 3 * (2 * b + a);
82 b = 3 * a - 1
83 {b > 5}
84A: 3 * a - 1 > 5
85 {a > 2}
86 6 * 3b + 3a > 2
87 18b + 3a > 2
88 18b > 2 - 3a
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